$\lim_{x\to1}\left(\left(x-1\right)^{-3}.\ln\left(1+3\ln\left(x\right)\right)\right)$
$3\cdot\left(-1.45\right)^2+3\left(-1.45\right)-2$
$2x-5y-4z=-20$
$ux^2+uv^2=vx^2$
$\frac{x^2-5x+3}{x^1-4}$
$\left(-6\right)^{17}$
$\left(5x-15\right)\left(5x+15\right)$
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