$-4x^2=0$
$\int\frac{\left(3x+6\right)}{3x^3+2x^2-3x}dx$
$-5x^2z^2\cdot2xy$
$\int\left(\frac{\sqrt{2x-4}}{x}\right)dx$
$\int\left(\frac{6x^3+2x^2-x}{x^5}\right)dx$
$49g+84g+6$
$\frac{625}{-5}$
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