$4x^2+4y^2=\:\:$
$\cos\left(9x\right)=0.3$
$3x-\frac{1}{2y}+2\:\frac{2}{3}y-\frac{5}{6x}$
$\lim_{x\to3}\left(\frac{x^2+6x+9}{x^2+2x-3}\right)$
$\left(8w^4\:+w^3\:\right)^2$
$\frac{dy}{dx}=\frac{4x}{x\left(y-2\right)}$
$\int\frac{4}{\left(x-4\right)\left(x^2+2x+6\right)}dx$
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