$\frac{x-6}{x^2-36}$
$\sqrt{\left(3x^2+1\right)^2}$
$\lim\:_{x\to\:+\infty\:}\left(x\sqrt{x+2}-\sqrt{x^3+1}\right)$
$\frac{2x^3+x^2}{x+1}$
$x^2-16x+24=0$
$\sqrt{1.25}$
$2x-3x$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!