$16x^6-56x^3y^4+49y^8$

$498^2$

$+\left(-11\right)+\left(-10-\left(-9\right)\right)$

$-\left(-12\right)+6-\left(+2\right)-6+\left(-7\right)-2$

$\cot^2\left(\infty\right)=\cos^2\left(\infty\right)+\left(\cot\left(\infty\right).\cos\left(\infty\right)\right)^2$

$\int\frac{3}{\left(1-x^2\right)}dx$

$3\cdot5\cdot6$