$\frac{-9}{\left(-1+x^2\right)x+3\left(x-3\right)}$
$10-\left(4-3\right)$
$x\:\left(x+16\right)$
$f\left(x\right)=\left(x^2+4x-5\right)^2$
$\left(x\:-\:9\right)\:\left(x+9\right)$
$-1-3^2-2^2$
$\lim_{n\to\infty}\frac{\left(\sqrt{10n^2+7n+3}\right)}{n^2}$
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