$\frac{\cos\left(x\right)}{1+\sin\left(x\right)}-\tan\left(x\right)=\sec\left(x\right)$
$\lim_{x\to\infty}\left(\frac{2x}{3x+5x^3}\right)$
$8xy^216x^640x^4$
$9y+\left(-7x\right)-3x+1-6y+4$
$\left(1+sin\:x\right)\left(sec\:x\:-\:tan\:x\right)$
$\int\frac{4}{x^3+3x^2+2x}dx$
$\int\frac{2}{2u+1}dx$
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