$\frac{dx}{dt}=-\frac{4k^2}{m^2t}$

$\left(2x+4y\right)$

$\frac{dy}{dx}=x^4+\left(\frac{y}{x}\right)$

$\lim_{x\to0}\left(\left(512-9x^6\right)^{\frac{1}{3}}-\left(512-9x^3\right)^{\frac{1}{3}}\right)$

$\left|\left(m+1\right)-\left(2m+3\right)\right|^2$

$5x^2-15x+10$

$a\frac{4}{5}b\frac{3}{2}$