$4x^4-12x^3+9x^2$
$4\tan\left(x\right)+3=-1$
$\sqrt{4}\cdot\sqrt{3}$
$\int\:\frac{-6x^2}{\sqrt[3]{3-4x^3}}dx$
$9x\:\:\sqrt{32x^3}y$
$\frac{dy}{dx}=20-\frac{x}{15}$
$\frac{x^{2}+7x+12}{x+2}$
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