$-13\cdot16$
$-7+\log_{11\:}k=-3$
$2x-4<34-x$
$\int\frac{2x^2-5x+4}{\left(x-3\right)\left(x+3\right)}dx$
$\left(x^2+2xh+h^2-8\right)^2$
$6x^2-4=10x$
$3.6+5.7$
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