$4x^2+3y^2+5x^2+x^2-3y$
$3\:\frac{3}{5}\cdot5$
$\left(x-1\right).\left(x+2\right)\le x^2+1$
$\sqrt{\frac{4}{9}}+\frac{1}{3}$
$-35+-3+-38$
$\int\frac{2x+3}{x^2+3x}dx$
$12x^2-72x+96$
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