$\lim_{x\to0}\left(4x^{\sqrt{3x}}\right)$
$\frac{64m^6-1}{2m-m}$
$a+b=135$
$\frac{dy}{dx}=\sqrt{105}$
$3x^2-2x-6>0$
$\left(3v^2-4u^2\right)^3$
$-2x^2-2x-1=0$
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