$x^2+6x+9=10$
$\left(a^2-26\right)^3$
$\left(+1.1\right)x\left(-19.1\right)$
$\sqrt{5x+1}=6$
$\int\:\left(\sqrt[3]{x}+x^2-5\right)\left(x^2-\frac{1}{x}\right)^2dx$
$2x\:-\:12\:+\:3x\:\:8\:+\:2x\:-\:2$
$f\left(x\right)=\left(7x+1\right)^5$
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