$\frac{\tan^2\left(x\right)}{\csc\left(x\right)}$
$4-\left(1-10x\right)$
$\frac{8+x}{3}+\frac{8+x}{3}$
$\frac{12x\:+\:8}{3x^2+4x}$
$\left(\sqrt{3y\:}-1\right)\left(\sqrt{3y}+1\right)$
$1+tan^2\:y$
$+2+\left(+8\right).\left(6\right)-\left(-7+6\right)$
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