$\lim_{x\to0}\left(\frac{8\:cos\left(0.01\right)-8\:}{0.01}\right)$
$\cos\left(x\right)=-0.7561$
$-\frac{1}{3}x\cdot6x^4-3x^2+9x-3$
$\int x\left(2x^3+\frac{1}{3x^2}\right)\left(x^5+4\right)dx$
$\frac{x^4}{1+x^3}$
$-3\left(6x^2-10x+9\right)+8\left(3x+4\right)$
$+8+15+16+17$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!