$\:\frac{3x+2}{5}\:<x-4$

$\frac{1-2\sin^2\left(x\right)}{cos\left(x\right)+\sin\left(x\right)}=\cos\left(x\right)-\sin\left(x\right)$

$4\cdot x^2-1+x'=0$

$\frac{x^2y^2}{\left(1+x\right)}-\frac{dx}{dy}=0$

$\frac{dy}{dx}\left(y^2=7x^2+6x\right)$

$x^2-8x-48\le0$

$\left(\frac{3x-2}{x+5}\right)^3$