$37-\left(-54\right)$
$a^2+4a-12=0$
$\left(\frac{x^{-2}y}{z^2}\right)^{-4}$
$m-2^3$
$\frac{4x-2}{3}=-6$
$\left(3x^3-7x^2+2x-12\right)\left(10x^3-6x^2-2x-8\right)$
$3\sqrt{5a}.-3\sqrt{20a^3}$
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