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Exercise

$x^2+16>0$

Step-by-step Solution

1

Moving the term $16$ to the other side of the inequation with opposite sign

$x^2>0-16$
2

Subtract the values $0$ and $-16$

$x^2>-16$
3

Removing the variable's exponent

$\sqrt{x^2}>\sqrt{-16}$
4

Calculate the power $\sqrt{-16}$ using complex numbers

$\sqrt{x^2}>4i$
5

Cancel exponents $2$ and $1$

$x>4i$

Final answer to the exercise

$x>4i$

Try other ways to solve this exercise

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  • Integrate by partial fractions
  • Product of Binomials with Common Term
  • FOIL Method
  • Integrate by substitution
  • Integrate by parts
  • Integrate using tabular integration
  • Integrate by trigonometric substitution
  • Weierstrass Substitution
  • Prove from LHS (left-hand side)
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Similar Questions Solved

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$x^2-25\ge0$

$x^2+11x<-18$

Main Topic: Inequalities

In mathematics, an inequation is a statement that an inequality holds between two values. It is usually written in the form of a pair of expressions denoting the values in question, with a relational sign between them indicating the specific inequality relation.

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