$x\left(3x-5\right)=-2$
$\frac{dt}{dv}=\left(v-\sqrt{10}\right)^2$
$-\frac{8}{2-4}$
$\left(\frac{1}{4}-7z^3\right)^2$
$\frac{2}{x+1}+\frac{1}{x+2}$
$-23x^2+68x+3=0$
$-\left[-6+8\right]:\left(-2\right)$
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