$\lim\:_{x\to\:0}\left(\frac{e^{4x}-1}{2x}\right)$
$\cos=0.79$
$\frac{csc\left(x\right)+t}{cot\left(x\right)}=\frac{cot\left(x\right)}{csc\left(x\right)-1}$
$\lim_{h\to0}\left(\frac{0}{h}\right)$
$y'=t-y$
$\:f\left(x\right)\:=\:2\:x\:2+1\:\:\:$
$\left(3x^2+7\right)\left(6-5x\right)$
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