$\left(3e^{-\infty}\right)^{\frac{1}{3\left(\infty\right)}}$
$b^2+7b=8$
$\lim_{x\to\infty}\left(\frac{3x^4-2x^2+1}{8x^3+2x+3}\right)$
$\frac{0}{8x^3}$
$4-2x>10-5x$
$\int\frac{1}{x\left(x^2-16\right)}dx$
$3x^2+12x+19$
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