$x^2<3x+4$
$35qr+2qr+50q-8q-17q$
$\frac{3\left(x+4\right)}{6}-\frac{x-2}{5}=\frac{3}{10}\left(x+8\right)$
$3x^2\left(4x+5\right)$
$-285-\:-12$
$\frac{149.55556}{73.77778}$
$\int\left(-sen\left(-2x\right)\right)dx$
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