$\int12\left(4x+1\right)^3dx$
$5,630\:+\:-400,298\:$
$\left(3x^2-2yz^3\right)\cdot\left(3x^2-2yz^3\right)$
$\frac{x^2+2x-6}{x+3}$
$\left(n+3\right)\left(n+5\right)\left(mn+n\right)$
$3x<5x-10$
$\lim_{x\to\infty}\left(\frac{1}{x\left(tan\left(x\right)\right)}\right)$
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