$\frac{d}{dx}\left(\sqrt[4]{1-3x}\right)$
$\left(3y^2-4h\right)\left(3y^2+4h\right)$
$2^{2x-4}=16$
$57^2$
$2cos2x+2cosx=0$
$3x^2-x\left(12x-4\right)$
$\frac{2}{x}=\frac{x}{5x+1}$
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