$84.5\cdot2$
$\:|-7|\:-\:\left(12\:-\:\left(-6\right)\right)$
$\int\frac{x^3+4x}{x^2-1}dx$
$\lim_{x\to-\infty}\left(\left(6-x\right)e^{\frac{x-4}{3}}-1\right)$
$\left(3x-5xy\right)^2$
$\int\cot^5\left(x\right)dx$
$\left(x^3-6x+\frac{5}{\sqrt{x}}\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!