$\left(2x^3-6x\right)^2$
$\lim_{x\to\infty}\left(\frac{x^x}{\left(1.004\right)^x}\right)$
$\left(13a-10b\right)^2$
$\frac{3^n}{n}x^n$
$4\sec\left(x\right)+\tan\left(x\right)$
$\lim\:_{x\to\:0}\left(\frac{x^3-x^2}{cosx-1}\right)$
$6x^2-3y^2=1$
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