$- 1 x ^ { 2 } + 4 x + 3$
$3x^2+6x+2x+4x^2$
$\int\frac{9x-8}{\left(x-3\right)\left(2x-5\right)}\:dx$
$\frac{0.98}{5}$
$\arcsin\left(3.742\right)$
$3\frac{5}{x}$
$\left(-24\right).7$
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