$\:x^2-2x\le\:2\:$

$\int6\left(6x-5\right)^4dx$

$\int\frac{2}{\left(x+3\right)\left(x-3\right)}dx$

$f\left(x\right)=\left(x^2-4x+2\right)\left(2x^3-x^2+4\right)$

$t^{-5}\frac{dy}{dx}=7$

$\left(tan\:a+cot\:a\right)^2=sec^2a+cosec^2a$

$\frac{8}{25}-\frac{1}{10}\le\frac{7}{10}x+\frac{3}{5}$