$2x^4-12$
$\left(\frac{\left(-6^2\right)-\left(-2^2\right)}{\left(-2^2\right)-\left(-6^2\right)}\right)$
$4x-1>2x-9$
$-4x+y=17$
$2.40+5+30+3.24+7.57+22.62$
$\frac{dy}{dx}=x^2+5+3x$
$\int\left(\frac{1}{x^2}\:\left(1+\frac{1}{x}\right)^3\right)dx$
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