$3-x=7$
$\frac{107.6}{120}$
$\frac{\left(4x^3-2x^2+20\right)}{\left(2x+3\right)}$
$-6v-33$
$\int\left(u+8\right)\left(4u+9\right)du$
$\ln\left(x\right)=24$
$\int19x\left(ln\left(4x\right)\right)^2dx$
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