$\frac{x^3-ax}{x^2+2}$
$\frac{4^3}{2^6}$
$\frac{\left(\left(-1\right)^n\cdot n^{\frac{1}{2}}\left(3x+1\right)^{n+1}\right)}{2^n\left(2n+2\right)}$
$4.008\cdot0.13$
$x4;y=-2;z$
$4x+2y+3z=1$
$\left(3b^2\cdot2b^3\cdot b\right)^2$
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