$\left(\frac{\sqrt[3]{1+0}-\sqrt{1-0}}{-2\cdot0}\right)$
$\left(2x-5\right)\left(3x^{2}-2x+6\right)$
$x^2+6=0$
$4x^2+3x-10$
$45a^2+81b^2$
$-2-4:2+5$
$\tan\left(x\right)=\frac{4}{5}$
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