$\lim_{x\to\frac{-1}{3}}\left(\frac{1}{9}-x^2\right)$
$\left(3^4\right)+\left(3^3\right)$
$-19x+19z+15x-31z$
$25:\:5\:+\:3\:x\:7\:\:$
$x<12-3x$
$16-\left(-3\right)^4:\left(-3\right)^3$
$\frac{sin^4x}{2}+\:\frac{cos^4x}{3\:}\:=\:\frac{1}{5}$
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