$\log_{12}\left(-3x+6\right)=\log_{12}\left(2x+6\right)$
$\frac{dh}{dt}=-\frac{3}{100}\cdot sqrt\left(h-15\right)$
$\left(3u^{-3}v\right)^2$
$7+5inx=2$
$5+3x\:\ge4-x$
$16x^2-\left(y-1\right)$
$2x-3\ge x+2$
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