$dx=x^2dy$
$4\sqrt{x^3}$
$\frac{dy}{dx}=-e^{2\left(x+y\right)}$
$\left(2x^3+3x\right)^3$
$\frac{1}{x}\log_{10}\left(10^x\right)$
$\frac{\cot\left(y\right)}{1-\sin^2\left(y\right)}$
$y'=6xy-2x$
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