$-x^2+7x$
$-\sqrt[6]{64}$
$\left(x^4\right)^33\left(x^2\right)^2-1\left(-2x^2\right)^5\left(3x^2\right)^3$
$sin\theta\:=\frac{3}{7}$
$64x^2\:-\left(2x-1\right)^2$
$\left(5x^2-2x^4+5\right)-\left(8x^2-5x-2\right)$
$4\left(8-3\right)-3\left(3-2\right)$
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