$3c+3c$
$\int x\left(x+5\right)^4dx$
$\int\arccos mxdx$
$\left(2x+3\right)^2=x^2+\left(3x-3\right)^2$
$\frac{1-2-2-3}{2}$
$2x-7\le1$
$-2\csc^2\left(2x\right)=0$
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