4cos2x−1=04cos^2x-1=04cos2x−1=0
7+267+2^67+26
limx→0(ln(x+1)sinxe3x−1)\lim_{x\to0}\left(\frac{ln\left(x+1\right)sinx}{e^{3x}-1}\right)x→0lim(e3x−1ln(x+1)sinx)
−38656 : (+604)-38656\::\:\left(+604\right)−38656:(+604)
12x+13x=5\frac{1}{2}x+\frac{1}{3}x=521x+31x=5
ab2−a+1−b2ab^2-a+1-b^2ab2−a+1−b2
5010\frac{50}{10}1050
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