$\left(x^2+2a\right)^5$
$\int\frac{1}{m+m^3}dm$
$1\cdot n$
$6b\left(4\right)+4b\left(4\right)$
$\frac{dy}{dx}=e^{-y}\left(3x-4\right)$
$10^5\cdot10^{-6}$
$\int\frac{5}{\left(x^2+2x-24\right)}dx$
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