$\left(-\frac{7a^2b^3c^0}{3a^2b^3c^7}\right)^{-4}$
$\left(4c-3\right)^3$
$3\sqrt{c}-1=\sqrt{c}+1$
$-9x^2+x+5x^5$
$\left(2x^5+3x^2\right)^5$
$-5x-4x-8y+9y-7x$
$\left(-1\right)x\left(-1\right)^0x\left(-1\right)^2$
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