$\frac{81y^2-9x^2}{9y+3x}$
$\int\frac{4x^2+38x+79}{\left(x+3\right)^3\left(x+5\right)}dx$
$\:2x+\frac{1}{x+1}=\:\frac{7}{2}$
$-19+3-7-5+2$
$\arccos\left(x\right)+\:\arctan\left(2\right)=\frac{\pi}{2}$
$x^2+7>4x$
$\left(2y^2+4\right)\left(2y^2-3\right)$
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