$\left(13.4\right).\left(\frac{22.3}{1}\right).\left(\frac{2.06}{1}\right)$

$\frac{1}{6}x^2+\frac{1}{6}x$

$\sqrt[5m]{2}\cdot\sqrt[4m]{2}$

$\left(x^3-3x^2+4x+k\right)\left(x-2\right)$

$-6xy-8+5x^2+6xy-9$

$8x-6=6x+4$

$\int\frac{\left(x^5\right)}{\left(x^3+1\right)^2}\:dx$