$3^2.3^2.3$
$\frac{6}{n+3}+\frac{20}{n^2+n-6}=\frac{5}{n-2}$
$x^2+16x-12$
$3^4\:x\:\:3^4\:x\:3^{-2}$
$\left(\frac{1}{2}m-\frac{1}{5}n\right)^3$
$\lim_{x\to\infty}\left(ln9x-ln\left(x+4\right)\right)$
$\left(10a+6\right)\left(10a-6\right)$
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