$\infty^2-5\left(\infty\right)+3$
$10m^2+39m+35$
$\frac{d}{dx}4x^2+9y=36$
$5v^6\cdot6v^5$
$\left(-10\right)\:x\:\left(+1\right)\:+\:\left(+2\right)$
$\lim_{x\to2}\frac{4-x^2}{3-\sqrt{x^2+5}}$
$\:\:\left(-1\right)\left(-2\right)\left(0\right)\left(-3\right)\left(-3\right)\left(3\right)$
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