$\int\frac{1}{5}\left(5x-3\right)dx$
$\frac{x^4-1}{x^2+2x}$
$18m-9$
$\frac{d}{dx}3y^4+6xy+4x=9$
$\frac{2\sec\left(x\right)}{1+\tan^{2}\left(x\right)}=-1$
$y'+100y=1$
$\int_0^{10}10e^{-10}dx$
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