$\frac{\left(4x^{2\:}\right)}{\left(3+4x^3\right)^2}$
$x^2+5x-225=0$
$\left(7x^3+5y\right)\left(5y-7x^3\right)$
$\frac{dy}{dx}\left(\frac{2}{3}x\right)$
$x^3\left(\sqrt[3]{x^3+1}\right)$
$9^8\cdot9^{-5}$
$81x^4y^2-90a^3x^2y+25a^6$
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