(x3−8)(x−2)\left(x^3-8\right)\left(x-2\right)(x3−8)(x−2)
y2−2⋅y.0+02y^2-2\cdot y.0+0^2y2−2⋅y.0+02
limx→−∞(2ln(−x)+4x)\lim_{x\to-\infty}\left(2ln\left(-x\right)+4x\right)x→−∞lim(2ln(−x)+4x)
∫(x⋅sqrt(12+2x))dx\int\left(x\cdot sqrt\left(12+2x\right)\right)dx∫(x⋅sqrt(12+2x))dx
sin(x)cos2(y)dx−cos(x)sin(y)dy=0sin\left(x\right)cos^2\left(y\right)dx-cos\left(x\right)sin\left(y\right)dy=0sin(x)cos2(y)dx−cos(x)sin(y)dy=0
16x6−2x3y2+yy41616x^6-2x^3y^2+y\frac{y^4}{16}16x6−2x3y2+y16y4
(2ysenx⋅cosx+y2senx)⋅dx + (sen2x−2ycosx)⋅dy=0\left(2ysenx\cdot cosx+y^2senx\right)\cdot dx\:+\:\left(sen^2x-2ycosx\right)\cdot dy=0(2ysenx⋅cosx+y2senx)⋅dx+(sen2x−2ycosx)⋅dy=0
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