$\lim_{x\to0}\left(\frac{2x^2-x}{x}\right)$
$\sqrt{x^2+6x}=4$
$\left(v-6x+4\right)\left(2v-3x-6\right)$
$144x^4-\frac{1}{16}y^6$
$x^3+5x^2-9x=0$
$125^{x-1}=25^{x+1}$
$\frac{26x\:-2}{x\:-5}$
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