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Exercise

$simplyfy\:\frac{\sin\:^2\left(\theta\:\right)}{1-\sin\:^2\left(\theta\:\right)}$

Step-by-step Solution

1

Apply the formula: $a\frac{b}{c}$$=\frac{ba}{c}$, where $a=simplyf$, $b=\sin\left(yt\right)^2$ and $c=1-\sin\left(\theta\right)^2$

$\frac{simplyf\sin\left(yt\right)^2}{1-\sin\left(\theta\right)^2}$

Final answer to the exercise

$\frac{simplyf\sin\left(yt\right)^2}{1-\sin\left(\theta\right)^2}$

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