$\lim_{x\to0}\left(\frac{x^2+6}{x}\right)$
$-\left(-5+7-3\right)-\left(7-2\right)\cdot\left(-2\right):\left(-4+2x\left(-4+6\right)-2\right)$
$\:\:\frac{5^3}{5^2}$
$\left(\frac{1}{3}b^3-20\right)^3$
$2x^2-14x+15$
$\:11x\frac{1}{3}$
$3a^2-2a+4$
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